Question

A 3.0-cm-tall object is 60 cm in front of a converging lens that has a 30cm focal length. Calculate the image position. Express your answer with the appropriate units.

Answer 1

Using the thin-lens equation, we find that the image position for an object placed 60 cm in front of a converging lens with a focal length of 30 cm is at 60 cm from the lens on the opposite side.

Step-by-step explanation:

To calculate the image position for an object in front of a converging lens, we use the thin-lens equation, which is 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance.

In this case, the object is 3.0 cm tall and placed 60 cm (do = 60 cm) in front of a converging lens with a focal length of 30 cm (f = 30 cm). Plugging these values into the thin-lens equation gives us:

1/30 cm = 1/60 cm + 1/di

This simplifies to:

1/di = 1/30 cm - 1/60 cm

After finding a common denominator and subtracting, we get:

1/di = 2/60 cm - 1/60 cm

1/di = 1/60 cm

Thus, di = 60 cm. The image is formed 60 cm from the lens on the opposite side.