Final answer:
The work done by the warehouse worker on the 15-kg crate, when pulling with a 69 N force at a 30° angle for a distance of 10 m, is approximately 600 joules.
Step-by-step explanation:
The student asked how much work is done on a 15-kg crate by a warehouse worker who pulls on it with a rope inclined at a 30° angle with the horizontal. The tension in the rope is 69 N and the crate slides 10 m along the horizontal floor.
To calculate the work done (W), we can use the formula W = F × d × cos(θ), where F is the force applied, d is the distance moved by the object, and θ is the angle the force makes with the direction of displacement.
In this case, only the horizontal component of the force does work because the displacement is horizontal. Therefore, the horizontal component of the force Fx = F × cos(θ) = 69 N × cos(30°).
The work done by the worker on the crate is then: W = Fx × d = (69 N × cos(30°)) × 10 m. Calculating this gives us a work of approximately 600 J (joules).