Final answer:
The given question asks for the instantaneous current in an RLC series circuit which requires the impedance and the phase relationship between voltage and current. Without the phase information, the instantaneous current cannot be accurately calculated. Methodology would involve calculating impedance followed by applying Ohm's law.
Step-by-step explanation:
The question involves determining the instantaneous current (i) in a series RLC circuit when it is driven by an oscillator at a given frequency. To solve for the current, one would need to calculate the impedance of the circuit and then apply Ohm's law. However, the question seems incomplete as it provides the peak voltage and the components of the circuit but does not mention the phase relationship between voltage and current necessary to find the instantaneous current. Still, we can discuss the methodology on how we would approach such a problem.
For a series RLC circuit, impedance (Z) is found using the formula Z = √(R^2 + (XL - XC)^2), where R is the resistance, XL is the inductive reactance (XL = 2πfL), and XC is the capacitive reactance (XC = 1 / (2πfC)). Once impedance is calculated, the root-mean-square (rms) current (Irms) can be found by dividing the rms voltage by the impedance (Irms = Vrms / Z). However, given that we are starting with peak voltages, we would need to use peak values in our calculations or convert them to rms first.
Nevertheless, to find the precise instantaneous current, we would need more information about the phase difference between the current and voltage or be given a specific point in the oscillation cycle.