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If an inductor carrying a 1.95 A current stores an energy of 0.250 mJ, what is its inductance?

User AlexGad
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1 Answer

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Final answer:

The inductance of the inductor is approximately 26.8 mH.

Step-by-step explanation:

The energy stored in an inductor is given by the equation E = (1/2)LI^2, where E is the energy stored, L is the inductance, and I is the current flowing through the inductor. In this case, the energy stored is given as 0.250 MJ, and the current is 1.95 A. Plugging these values into the equation, we have:

E = (1/2)L(1.95)^2

0.250 × 10^-3 = (1/2)L(1.95)^2

Simplifying and solving for L, we find that the inductance is approximately 26.8 mH.

User John David Five
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