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Johny left his house at 9:00 am to visit his friend Allen, who lived 3 km away. Johny jogged at a rate of 2 m/s. What time was it when he arrived at Allen's house?

a) 9:45 am
b) 9:30 am
c) 9:15 am
d) 9:06 am

User Ordo
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1 Answer

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Final answer:

Johny arrived at Allen's house at 9:25 am after jogging for 25 minutes at a rate of 2 m/s over a distance of 3 km.

Step-by-step explanation:

Johny left his house at 9:00 am to visit his friend Allen, who lived 3 km away. Johny jogged at a rate of 2 m/s. To find out what time Johny arrived at Allen's house, we first need to calculate the total time taken for the jog. Here's the formula to calculate the time taken:

Time = Distance / Speed

We will convert the distance from kilometers to meters to match the units of speed:

3 km = 3 × 1000 m = 3000 m

Now, we use the formula with Johny's speed and distance:

Time = 3000 m / (2 m/s) = 1500 s

Next, we'll convert seconds to minutes

1500 s = 1500 s / 60 s/min = 25 min

Finally, we add the 25 minutes to the departure time of 9:00 am

Arrival Time = 9:00 am + 25 min = 9:25 am

User Erik Pearson
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