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A beam of light with a wavelength of 540 nm is shone at two

slits that are separated by a distance of 2.8 x 10-6 m. Calculate
the angle formed between the central maximum and the second-order
maximum.

1 Answer

4 votes

Final answer:

The angle between the central maximum and the second-order maximum is approximately 0.387°.

Step-by-step explanation:

To calculate the angle between the central maximum and the second-order maximum in a double-slit experiment, we can use the equation: sin(θ) = m * λ / d, where θ is the angle, m is the order of the maximum, λ is the wavelength of the light, and d is the separation between the slits.

In this case, the wavelength of light is 540 nm and the separation between the slits is 2.8 x 10^-6 m. Since we want to find the angle between the central maximum (m=0) and the second-order maximum (m=2), we can substitute these values into the equation:
sin(θ) = 2 * 540 nm / 2.8 x 10^-6 m

Using a scientific calculator, we can solve for θ and find that the angle is approximately 0.387°.

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