Final answer:
The initial kinetic energy of a 1300 kg car traveling at 27 m/s is 474,450 J or 474.45 kJ.
Step-by-step explanation:
The question is asking to calculate the initial kinetic energy of a 1300 kg car traveling at 27 m/s before it comes to a stop. The kinetic energy (KE) of an object can be calculated using the formula KE = 0.5 × mass × velocity2. In this case, we replace 'mass' with 1300 kg and 'velocity' with 27 m/s.
Calculation:
KE = 0.5 × 1300 kg × (27 m/s)2
KE = 0.5 × 1300 × 729
KE = 650 × 729
KE = 474,450 J or 474.45 kJ
So, the initial kinetic energy of the car was 474,450 joules or 474.45 kilojoules.