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What would be the apparent frequency of 2000 Hz train whistle

that is moving towards a stationary observer at 40.0 m/s on a 20 C
day?

User EpicAdv
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1 Answer

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Final answer:

The apparent frequency of a 2000 Hz train whistle moving towards a stationary observer at 40.0 m/s can be calculated using the Doppler effect formula. Substituting the values into the formula, the apparent frequency is approximately 1777 Hz.

Step-by-step explanation:

The apparent frequency of a train whistle can be calculated using the Doppler effect formula:

f' = (v + vo) / (v + vs) * f

Where:

  • f' is the apparent frequency heard by the observer
  • v is the speed of sound (331 m/s at 20 C)
  • vo is the speed of the observer (0 m/s as they are stationary)
  • vs is the speed of the source (40.0 m/s for the train)
  • f is the actual frequency of the train whistle (2000 Hz)

Substituting the values:

f' = (331 + 0) / (331 + 40.0) * 2000

Simplifying the equation:

f' = 331 / 371 * 2000

f' ≈ 1777 Hz

Therefore, the apparent frequency of the 2000 Hz train whistle that is moving towards a stationary observer at 40.0 m/s on a 20 C day is approximately 1777 Hz.

User SpectralWave
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