Question

Let L=1.72m , d=0.77m , Q1=−5.57μC , and |Q2|=14.6μC . Calculate

the magnitude of the force, in newtons, that the rod exerts on the
point charge at the origin.

Answer 1

The magnitude of the force between two charges can be calculated using Coulomb's Law formula.

Step-by-step explanation:

The magnitude of the force between two point charges can be calculated using Coulomb's Law formula:

F = k * |Q1| * |Q2| / r^2

where F is the magnitude of the force, k is the electrostatic constant (9 * 10^9 N m^2 / C^2), |Q1| and |Q2| are the magnitudes of the charges, and r is the distance between the charges.

In this case, Q1 = -5.57 * 10^-6 C, Q2 = 14.6 * 10^-6 C, and the distance between the charges is d = 0.77 m

Substituting these values into the formula, we get:

F = (9 * 10^9 N m^2 / C^2) * (-5.57 * 10^-6 C) * (14.6 * 10^-6 C) / (0.77 m)^2

Calculating this expression will give us the magnitude of the force in Newtons.