228k views
0 votes
Graph the line that passes through the points (-2, 5) and (-1, 2), and determine the equation of the line. What is the equation of the line in slope-intercept form?

A) y = 3x + 1
B) y = -3x - 1
C) y = 1/3x + 1
D) y = -1/3x - 1

User Bokmann
by
7.9k points

1 Answer

3 votes

Final answer:

To find the equation of the line passing through the points (-2, 5) and (-1, 2), we first find the slope using the formula (y2 - y1) / (x2 - x1). Then, we can use the point-slope form to write the equation. Finally, we can simplify it to get the equation in slope-intercept form (y = mx + b) by solving for y.

Step-by-step explanation:

To graph the line that passes through the points (-2, 5) and (-1, 2), we first need to find the slope of the line. The slope is the change in y divided by the change in x. Using the formula:

slope = (y2 - y1) / (x2 - x1)

Plugging in the values (-2, 5) and (-1, 2), we get:

slope = (2 - 5) / (-1 - (-2)) = -3 / 1 = -3

Now that we have the slope, we can use the point-slope form of the equation:

y - y1 = m(x - x1)

Substituting the values (-2, 5) and -3 for m, we get:

y - 5 = -3(x - (-2))

Simplifying the equation gives:

y - 5 = -3(x + 2)

Finally, we can rewrite the equation in slope-intercept form (y = mx + b) by solving for y:

y = -3x - 6 + 5y = -3x - 1

The equation of the line in slope-intercept form is y = -3x - 1.

User Thinh Vu
by
7.3k points