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An electron moving at 4.0 ×10⁷ m/s is placed in the presence of a 1.0-T magnetic field and experiences a magnetic force of 4.8× 10⁻¹² is

User Foobnix
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Final answer:

To determine the angle between the electron's velocity and the magnetic field, the formula F = qvBsin(θ) is used, solving for θ yields two possible angles due to the nature of the sin-1 function.

Step-by-step explanation:

The student's question concerns the calculation of the angle between the velocity of an electron and a magnetic field when the electron is subjected to a known magnetic force. The magnetic force an electron experiences is given by the equation F = qvBsin(θ), where F is the force, q is the charge of the electron, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field direction. To find the angle, the equation can be rearranged to solve for θ, leading to θ = sin-1(F / (qvB)). Since sin-1 is a many-to-one function, there will be two possible angles between 0° and 180° that satisfy the equation.

User Cevin Ways
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