Question

How much charge is transferred from the battery to the capacitors as the capacitors charge? C₁=9×10⁻⁶F, C₂=4×10⁻⁶F ,C₃=?

Answer 1

The charge on the 4.20µF capacitor is 1.51x10^-4C.

Step-by-step explanation:

In a series connection, the same amount of charge flows through each capacitor.

The charge is given by the formula Q=CV, where Q is the charge, C is the capacitance, and V is the potential difference. So, for the 4.20µF capacitor, the charge is Q=(4.20x10^-6F)(36.0V) = 1.51x10^-4C. Therefore, the charge on the 4.20µF capacitor is 1.51x10^-4C.