Final answer:
The acceleration imparted to the paper by the boxer's punch is 483.33 m/s².
Step-by-step explanation:
The question is asking to calculate the acceleration imparted to a sheet of paper by a boxer's punch, which brought the paper from rest to a speed of 29 m/s in 0.060 seconds.
To find the acceleration, we can use the formula for acceleration (a) which is change in velocity (Δv) divided by time (t):
a = Δv / t
In this case, the change in velocity is 29 m/s since the paper started at rest (0 m/s) and ended at 29 m/s. The time over which this change occurred is 0.060 seconds.
a = 29 m/s / 0.060 s = 483.33 m/s²
Therefore, the acceleration imparted to the paper by the boxer's punch is 483.33 meters per second squared (m/s²).