Final answer:
To find the heat generated in a circuit over 2.50 seconds with a current of 5.00 Amperes and a resistance of 3.50 ohms, use the formula H = I^2 x R x t. The calculation yields 218.75 joules of heat.
Step-by-step explanation:
A current of 5.00 Amperes is maintained in a simple circuit with a total resistance of 3.50 ohms. The amount of heat generated in 2.50 seconds can be calculated using the formula derived from Joule's law, which states that the heat (H) generated in a resistor is equal to the product of the square of the current (I), the resistance (R), and the time (t) the current flows through it. The formula is H = I2 × R × t.
Substituting the given values:
- I = 5.00 Amperes (A)
- R = 3.50 ohms (Ω)
- t = 2.50 seconds (s)
We get H = (5.00 A)2 × 3.50 Ω × 2.50 s = 218.75 joules.
Therefore, the heat generated in the circuit over 2.50 seconds is 218.75 joules.