Question

A jitter Browi a 0.145kg base ball toward the batter so that it cross home patently and has a speed of 42 m/s before it makes contact with the bat. The better them wage back at the pitch with a spot of a mus. Assume the ball traxes along the same line leaving the bat astuned before contacting the bat.

what is the magnitude of the impulse delivered by the bot to the base ball?

Answer 1

The magnitude of the impulse delivered by the bat to the baseball is 12.18 kg m/s.

Step-by-step explanation:

Given:

Mass of the baseball, m = 0.145 kg

Initial velocity of the baseball, u = 42 m/s

The change in momentum (Δp) of the baseball can be calculated using the formula:

Δ p = Final momentum - Initial momentum \ Final momentum} = mass × final velocity

Assuming the baseball moves in the opposite direction after being hit by the bat with the same speed (42 m/s), the final momentum will be mass × (- final velocity.

Initial momentum = mass × initial velocity

Initial momentum = 0.145 kg × 42 m/s = 6.09 kg m/s

Final momentum = mass × (- final velocity)

Final momentum = 0.145 kg × (-42 m/s) = -6.09 kg m/s

Now, the change in momentum Δ p will be:

Δ p = Final momentum - Initial momentum

Δ p = -6.09 kg m/s - 6.09 kg m/s = -12.18 kg m/s

The magnitude of the impulse delivered by the bat to the baseball is -12.18 kg m/s = 12.18 kg m/s.