Question

A capacitor consisting of two concentric spheres of radius R1 and R2 2.00-R1 has a capacitance of C = 6,00 picofarads and is charged to a potential difference of 78.0 Volts. Calculate the energy stored in the capacitor.

Answer 1

The energy stored in a capacitor with a capacitance of 6.00 picofarads and charged to a potential difference of 78.0 volts is 9.126 x 10⁻² joules.

Step-by-step explanation:

To calculate the energy stored in the capacitor, we can use the formula for the energy stored in a capacitor, which is given by:

Energy (U) = ½ CV²

Here, C is the capacitance in farads and V is the potential difference in volts. The question provides the capacitance (C = 6.00 picofarads or 6.00 x 10⁻¹² F) and the potential difference (V = 78.0 volts).

Plugging in these values, we get:

U = ½ x 6.00 x 10⁻¹² F x (78.0 V)²

Calculate:

U = ½ x 6.00 x 10⁻¹² F x 6084 V²

U = ½ x 6.00 x 10⁻¹² F x 6084 J

U = 3.00 x 10⁻¹² F x 3042 J

U = 9.126 x 10⁻² J

Therefore, the energy stored in the capacitor is 9.126 x 10⁻² Joules.