Question

A point charge Q1 = −2.2×10−8 C remains at rest. A particle of 1.8×10−20 kg, +8×10−10 C, initially 10 cm from Q1, now travels 6 cm closer to Q1. During this trip, its speed changes from 7 × 106 m/s to 8 × 106 m/s. Find the change in potential from the initial to final positions.

Answer 1

The change in potential from the initial to final positions is -4.9 x 10^6 V

Step-by-step explanation:

The change in potential from the initial to final positions can be calculated using the formula for electric potential energy:

V = kQ1Q2/r

Where V is the potential, k is the Coulomb constant (9 x 10^9 Nm^2/C^2), Q1 is the charge of the fixed point charge Q1, Q2 is the charge of the particle, and r is the distance between the charges.

In this case, the initial distance is 10 cm and the final distance is 4 cm.

Using the given charges, we plug them into the formula to find the initial and final potentials, then subtract the initial potential from the final potential to find the change in potential.

The change in potential is -4.9 x 10^6 V.