Final answer:
The voltage change experienced by the charge when an electric field does 38 J of work on a charge of 0.0008 C is 47.5 kV.
Step-by-step explanation:
To find the voltage change when an electric field does work on a charge, we can use the relationship between work (W), charge (q), and voltage (V), given by W = qV. By rearranging this equation to solve for V, we get V = W/q. Plugging in the values given in the question, we calculate the voltage change as follows:
V = 38 J / 0.0008 C = 47500 V or 47.5 kV.
Thus, the voltage change experienced by the charge when the electric field does 38 J of work on a charge of 0.0008 C is 47.5 kV.