Final answer:
The elongation of a spring with a spring constant of 19 N/m when a 17 N force is applied is approximately 0.89 meters (or 89 centimeters).
Step-by-step explanation:
To determine the elongation of a spring when a force is applied, we use Hooke's Law, which is given by the formula F = kx, where F is the force applied, k is the spring constant, and x is the elongation of the spring. Given that a force of 17 N elongates a spring with a spring constant of 19 N/m, we can rearrange the formula to solve for x:
x = F / k = 17 N / 19 N/m = 0.8947 m
Thus, the elongation of the spring is approximately 0.89 meters (or 89 centimeters) when a force of 17 N is applied.