Final answer:
The time an armadillo takes to land is based on the initial vertical velocity and the height from which it jumps. For an initial vertical velocity of 14.3 m/s and a starting altitude dip of 20.0 m, the time in the air would be 3.96 seconds.
Step-by-step explanation:
The time for projectile motion is determined completely by the vertical motion. Therefore, if a startled armadillo jumps into the air with an initial vertical velocity of 14 f(t)/(s), which appears to be a typo and should likely be 14.3 m/s, it will take a specific amount of time to land back on the ground depending on the altitude from which it started. Using the given example for projectiles, any projectile with an initial vertical velocity of 14.3 m/s, landing 20.0 m below its starting position, will spend 3.96 seconds in the air. Similarly, a projectile with an initial velocity of 21.2 m/s, landing 10.0 m below its starting position, will spend 3.79 seconds in the air.