Question

A loop of area 0.250 m² is in a uniform 0.0200 -T magnetic field. If the flux through the loop is 3.8310⁻³ T⋅m³ , what angle does the normal to the plane of the loop make with the direction of the magnetic field?

Answer 1

The angle between the normal to the plane of the loop and the direction of the magnetic field is approximately 41.4°.

Step-by-step explanation:

The angle between the normal to the plane of the loop and the direction of the magnetic field can be calculated using the formula:

Φ = BA cosθ

Where Φ is the magnetic flux, B is the magnetic field strength, A is the area of the loop, and θ is the angle between the normal to the plane of the loop and the magnetic field. Rearranging the formula, we get:

cosθ = Φ / (BA)

Substituting the given values, we get cosθ = (3.8310⁻³ T⋅m³) / (0.0200 T * 0.250 m²) = 3.8310⁻³ / 0.0050 = 7.6620⁻¹ = 0.76620

Taking the inverse cosine of this value gives θ = cos⁻¹(0.76620) ≈ 41.4°