Final answer:
The question requires calculating the angular momentum of a bicycle tire, which involves Physics concepts such as rotational motion and moment of inertia. We use specific formulas to find the angular momentum, taking into account the tire's mass, radius, and angular velocity.
Step-by-step explanation:
The student is asking about calculating the angular momentum of a bicycle tire, which is a concept from Physics, specifically within the realm of rotational motion and conservation of angular momentum. The formula for angular momentum (L) is L = I × ω, where I is the moment of inertia and ω is the angular velocity. For a solid cylinder like a bicycle tire, the moment of inertia is given by I = (1/2) × m × r^2, where m is the mass and r is the radius. The angular velocity (ω) can be converted from revolutions per minute (rpm) to radians per second (rad/s) using the fact that 1 rev = 2π rad and 1 minute = 60 seconds.
In this case, the tire with a mass of 2.3 kilograms (kg) and a diameter of 0.51 meters (m) has a radius (r) of 0.255 m (since radius is half of the diameter). The tire is spinning at 150 rpm, which we will convert to rad/s by multiplying with {(2π rad) / (1 rev)} and dividing by 60 seconds. Substituting the values into the equations, we will find the tire's angular momentum.