Final answer:
To find the angle between a proton's velocity and a magnetic field when given the magnetic force, use the equation F = qvBsin(θ) to solve for θ by rearranging it to θ = arcsin(F/(qvB)). By substituting known values for F, q, v, and B, the angle θ can be calculated.
Step-by-step explanation:
The student's question pertains to determining the angle between a proton's velocity and a magnetic field based on the magnetic force experienced by the proton. The force experienced by a charged particle moving through a magnetic field is given by the equation F = qvBsin(θ), where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity of the particle and the magnetic field.
In this specific case, we have F = 8.00×10⁻¹³ N, the proton's charge q = 1.60×10⁻ C (elementary charge), its velocity v = 6.20×10⁶ m/s, and the magnetic field strength B = 1.76 T. To find the angle, we can rearrange the formula to θ = arcsin(F/(qvB)) and plug in the known values.
After calculating with these values, the angle θ can be determined, revealing the orientation of the proton's velocity relative to the magnetic field direction.