Question

A 4.9×10-2-T magnetic field passes through a circular ring of radius 3.0 cm at an angle of 19 degrees with the normal. Find the magnitude of the magnetic flux through the ring.

Answer 1

To calculate the magnetic flux through a circular ring, the equation Φ = BAcosθ is used, where B is the magnetic field strength, A is the area of the loop, and θ is the angle to the normal. The area of the ring is determined by A = πr^2 and then substituted into the flux equation along with the magnetic field and angle values.

Step-by-step explanation:

The student is asking about calculating the magnetic flux through a circular ring when the magnetic field is at an angle to the normal of the ring's plane. The magnetic flux, Φ, is given by the equation Φ = BAcosθ, where B is the magnetic field strength, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the plane of the loop.

To find the flux through the ring:

• First, calculate the area of the ring: A = πr^2, where r is the radius of the ring.
• Next, plug the area and given values into the formula for magnetic flux: Φ = (4.9×10^-2 T)(π)(0.03 m)^2cos(19 degrees).
• Finally, work out this calculation to determine the flux in webers (Wb).