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Calculate the strength and direction of the electric field E due to a point charge of 7.00 nC at a distance of 8.00 m from the charge.

User JohnRW
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Final answer:

The strength of the electric field E due to a point charge can be calculated using the equation E = kQ/r^2, where E is the electric field strength, k is the Coulomb's constant, Q is the charge, and r is the distance from the charge. To calculate the strength of the electric field due to a point charge of 7.00 nC at a distance of 8.00 m, plug in the values into the equation E = (k * Q) / r^2. The direction of the electric field is radially outward from the point charge.

Step-by-step explanation:

The strength of the electric field E due to a point charge can be calculated using the equation E = kQ/r^2, where E is the electric field strength, k is the Coulomb's constant, Q is the charge, and r is the distance from the charge.

To calculate the strength of the electric field due to a point charge of 7.00 nC at a distance of 8.00 m, we need to substitute the values into the equation:

E = (k * Q) / r^2

Plugging in the values, we get:

E = (8.99 x 10^9 Nm^2/C^2 * 7.00 x 10^-9 C) / (8.00 m)^2

Simplifying the equation gives:

E = 7.00 x 10^9 N/C

The direction of the electric field is radially outward from the point charge.

User Delby
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