Question

A rocket moves from 30.0 m/s to 120.0 m/s, accelerating at a

constant rate of 18.0 m/s2 . How far does the rocket travel during
this acceleration?

Answer 1

The rocket travels 375 meters while accelerating from 30.0 m/s to 120.0 m/s at a constant acceleration of 18.0 m/s², calculated using the kinematic equation that relates velocity, acceleration, and distance.

Step-by-step explanation:

To find the distance the rocket travels while it accelerates from 30.0 m/s to 120.0 m/s at a constant acceleration of 18.0 m/s2, we can use the kinematic equation which relates initial velocity (ν0), final velocity (ν), acceleration (a), and distance (s):

ν2 = ν02 + 2as

First, rearrange the equation to solve for s:

s = (ν2 - ν02)/(2a)

Now, plug in the values:

s = (120.0^2 - 30.0^2) / (2 * 18.0)

s = (14400 - 900) / 36

s = 13500 / 36

s = 375 m

Therefore, the rocket travels 375 meters during its acceleration.