Final answer:
The buoyant force on the ice floating freely in liquid water is 6.28 N.
Step-by-step explanation:
When an object floats in a fluid, the buoyant force on the object is equal to the weight of the fluid displaced by the object. In this case, the ice is floating in water, so the buoyant force on the ice is equal to the weight of the water displaced by the ice.
The volume of the ice can be calculated using the equation:
Volume = Mass / Density
Substituting the given values, we have:
Volume of ice = 0.590 kg / 917 kg/m³ = 0.000643 m³
The buoyant force on the ice can then be calculated using the equation:
Buoyant force = Weight of water displaced = Density of water x Volume of ice x Acceleration due to gravity
Substituting the given values, we have:
Buoyant force = 1000 kg/m³ x 0.000643 m³ x 9.8 m/s² = 6.28 N
Therefore, the buoyant force on the ice floating freely in liquid water is 6.28 N.