Final answer:
The height the ball reaches before stopping is approximately 62.8 meters.
Step-by-step explanation:
To find the height the ball reaches before stopping, we can use the equation:
final velocity (v) squared = initial velocity (u) squared + 2 imes acceleration (a) imes displacement (s)
Given that the ball is thrown upwards, the final velocity will be 0 m/s. The initial velocity (u) is 35 m/s and the acceleration (a) due to gravity is -9.8 m/s^2 (negative because it acts in the opposite direction to the motion of the ball).
Plugging in these values, the equation becomes:
0 = 35^2 + 2 imes (-9.8) imes s
Simplifying and solving for s, we find that the height the ball reaches before stopping is approximately 62.8 meters.