Question

Six litres of water whose density is 1(g)/(c)m³ is mixed with seven litres of alcohol whose density is 0.8(g)/(c)m³. Determine the density of the mixture in k(g)/m³.

Answer 1

The density of the mixture of water and alcohol is 892.31 kg/m³, calculated by combining the total mass of both liquids and dividing by the total volume of the mixture.

Step-by-step explanation:

To determine the density of the mixture of water and alcohol, first calculate the total mass and the total volume of the mixture. With the given densities, the mass of six liters of water is 6,000 g (since its density is 1 g/cm³ or 1,000 kg/m³), and the mass of seven liters of alcohol is 5,600 g (because its density is 0.8 g/cm³ or 800 kg/m³). The total mass of the mixture is 11,600 g, and the total volume is 13 liters. Convert the total mass into kilograms to be consistent with the SI units for density (1 kg = 1,000 g). So, the total mass in kilograms is 11.6 kg. Now, calculate the density using the formula density = mass/volume. The density of the mixture in kilograms per cubic meter (kg/m³) would thus be Density = (11.6 kg) / (0.013 m³) = 892.3077 kg/m³. Therefore, the density of the mixture is 892.31 kg/m³ when rounded to two decimal places.