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Consider a series RC circuit for which C=5.0 ApF, R=2.2×10⁶

n, and E=15 V.
(a) Find the time constant of the circuit

User MagikCow
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1 Answer

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Final answer:

The time constant of the RC circuit is found by multiplying the corrected resistance value, 2.2·¹³ Ω, by the capacitance value, 5.0 pF, resulting in a time constant of 11 ns.

Step-by-step explanation:

The question is asking to find the time constant of an RC circuit.

The time constant (τ) is calculated using the equation τ = RC, where R is the resistance and C is the capacitance. Given that the resistance (R) is 2.2×10¶ n (ohms) and the capacitance (C) is 5.0 ApF (attopico farads, which is a typographical error and should be interpreted as pF or picofarads), the time constant is found by multiplying the two values:

τ = R × C = (2.2×10¶ Ω) × (5.0 pF)

However, before multiplying, it is necessary to ensure that the units are consistent. If we assume that 'n' means nano (n), we need to convert it to standard units: 2.2×10¶ nΩ = 2.2×10^3 Ω (ohms), as 1 nano = 10^-9, and 1 pico = 10^-12, so 5.0 pF is 5.0×10^-12 F (farads).

Using these converted units:

τ = (2.2×10¶3) × (5.0×10^-12) = 11×10^-9 seconds or 11 ns (nanoseconds).

User Vasyl Khmil
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