Question

A 67.63 kg little buddy climbs 10.00 m up a pole at a constant

speed. If the student’s power output is 250.0 W, how long does it
take the student to climb the pole in seconds?

Answer 1

Using the power formula, the student will take approximately 1.07 seconds to climb the pole with a power output of 250.0 W.

Step-by-step explanation:

To calculate the time it takes for the student to climb a pole using a power output, we use the formula for power, which is power (P) equals work (W) divided by time (t). Work done is equal to force multiplied by distance. Since the student is climbing upwards against the force of gravity, the force here is equivalent to the student's weight, which is mass (m) times the acceleration due to gravity (g), and the work done is this force multiplied by the height (h) the student climbs. The acceleration due to gravity is approximately 9.81 m/s2.

In this case, we can rearrange the power formula to solve for time: t = W / P. Plugging in the values, we have:

t = (m * g * h) / P
= (67.63 kg * 9.81 m/s2 * 10.00 m) / 250.0 W
= (67.63 * 9.81 * 10) / 250
= 268.1513 / 250
= 1.0726052 seconds (rounded to seven decimal places)

So, the student will take approximately 1.07 seconds to climb the pole.