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A biconcave lens forms a virtual image 0.8 times the size of the object. The object distance is 23.1 cm. Find the focal length of the lens. Answer in units of cm and round to one decimal place.

User Rkrdo
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Final answer:

To find the focal length of the biconcave lens, we can use the thin lens formula and the magnification formula. The focal length is approximately -10.27 cm.

Step-by-step explanation:

The focal length of the biconcave lens can be found using the thin lens formula, which states that 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance. In this case, the lens forms a virtual image that is 0.8 times the size of the object, so the magnification (m) is -0.8. Using the magnification formula, m = v/u, we can rearrange it to find v/u = -0.8.

Since the image formed is virtual, the image distance (v) is negative. Substituting the given values, we have -0.8 = v/23.1. Solving for v, we find that v = -18.48 cm. Now, substituting the values of v and u into the thin lens formula, we have 1/f = 1/-18.48 - 1/23.1. Simplifying this equation, we get 1/f = -0.0541 - 0.0433, which gives us 1/f = -0.0974. Solving for f, we find that f = -10.27 cm.

User Rafid
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