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An electron is released 9.5 cm from a very long nonconducting rod with a uniform 5.6C /mWhat is the magnitude of the electron's initial acceleration?

User Pgrandjean
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Final answer:

The question is about calculating the initial acceleration of an electron placed in an electric field, using the charge density on a rod and the properties of an electron.

Step-by-step explanation:

The question involves determining the magnitude of the initial acceleration of an electron in an electric field. The electron's charge is -1.60 × 10-19 C and the mass of an electron is 9.11 × 10-31 kg. Given a uniform charge density (5.6 C/m) on a non-conducting rod, the electric field E at a distance r from a long charged rod can be calculated using Gauss's law. For a long rod, E = (λ / (2π ε0 r)), where λ is the charge per unit length and ε0 is the vacuum permittivity (8.854 × 10-12 C2/N·m2). Once the electric field E is known, the force on the electron can be found using F = qE, where q is the charge of the electron. Finally, the acceleration (a) can be calculated by using Newton's second law, a = F/m, where F is the force and m is the mass of the electron.

User Manish Sinha
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