Question

A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the equation z(t)=at²−βt³, where α=1.40 m/s² and β=0.0480 m/s³. Calculate the average velocity of the car for the time interval t=0 to t=2.00 s. Express your answer in meters per second. Part B Calculate the average velocity of the car for the time interval t=0 to t=3.90 s. Express your answer in meters per second. Calculate the average velocity of the car for the time interval t=2.00 s to t=3.90 s. Express your answer in meters per second.

Answer 1

To calculate the average velocity of the car for different time intervals, you need to find the displacement and divide it by the time interval.

Step-by-step explanation:

To calculate the average velocity of the car for the time interval from t=0 to t=2.00 s, we need to find the displacement of the car during this time interval and divide it by the time taken.

The displacement is given by subtracting the initial position (x(0)) from the position at t=2.00 s (x(2.00)).

The average velocity is then calculated by dividing the displacement by the time interval.

To calculate the average velocity for the time interval from t=0 to t=3.90 s, we follow the same steps as before.

The displacement is given by subtracting the initial position (x(0)) from the position at t=3.90 s (x(3.90)), and then we divide the displacement by the time interval.

To calculate the average velocity for the time interval from t=2.00 s to t=3.90 s, we again find the displacement by subtracting the position at t=2.00 s (x(2.00)) from the position at t=3.90 s (x(3.90)), and then divide the displacement by the time interval.