86.0k views
5 votes
Pointlike charged object has a charge of 50 nC. Test particle is

15 cm away from object and object exerts a force of 75 nN to test
particle. Find the charge of test particle.

1 Answer

7 votes

Final answer:

The charge of the test particle is 1.5 nC.

Step-by-step explanation:

To find the charge of the test particle, we can use Coulomb's Law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Let q1 be the charge of the point-like object, q2 be the charge of the test particle, and d be the distance between them.

Using the given information, we have:

q1 = 50 nC, F = 75 nN, and d = 15 cm.

Applying Coulomb's Law:

F = k * (q1 * q2) / (d^2)

Plugging in the values:

75 nN = (9 * 10^9 N * m^2 / C^2) * (50 nC * q2) / (0.15 m)^2

Simplifying and solving for q2:

q2 = (75 nN * 0.15 m^2) / (9 * 10^9 N * m^2 / C^2 * 50 nC)

q2 = 1.5 nC

Therefore, the charge of the test particle is 1.5 nC.

User Timothy Vann
by
7.4k points