Question

ball is thrown from a height of 44 meters with an initlal downward velocity of 6(m)/(s). The ball's height h (In meters ) after t seconds is given by the following. h=44-6t-5t²

Answer 1

This question pertains to the physics of projectile motion, focusing on the height of a ball over time when thrown from a height with an initial velocity.

Step-by-step explanation:

The student's question is related to projectile motion in physics. Specifically, it inquires about the height of a ball over time when it is thrown from a certain height with an initial downward velocity. The equation provided, h = 44 - 6t - 5t², represents the height h in meters of the ball after t seconds given that it was thrown from a height of 44 meters with an initial downward velocity of 6 m/s. Projectile motion is a common topic in high school physics, and it involves understanding how objects move under the influence of gravity alone after being projected with an initial velocity.