Final answer:
The speed of the proton after it is accelerated through an electric potential difference of 106 V is approximately 6.02 x 10^6 m/s.
Step-by-step explanation:
To calculate the speed of a proton that is accelerated from rest through an electric potential difference of 106 V, we can use the equation:
v = √(2qV/m)
Where v is the speed of the proton, q is the charge of the proton (1.6 x 10^(-19) C), V is the electric potential difference (106 V), and m is the mass of the proton (1.67 x 10^(-27) kg).
Substituting the values into the equation, we get:
v = √(2 x 1.6 x 10^(-19) C x 106 V / 1.67 x 10^(-27) kg) = 6.02 x 10^6 m/s
Therefore, the speed of the proton is approximately 6.02 x 10^6 m/s.