Question

Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. Assume free fall. If the faster stone takes 12.0 s to return to the ground, how long will it take the slower stor to return? Express your answer in seconds.

Answer 1

The time taken by the slower stone to return to the ground is 24.0 seconds.

Step-by-step explanation:

In this question, we are given that one stone is thrown vertically upward with three times the initial speed of the other stone. We are also given that the faster stone takes 12.0 seconds to return to the ground. We need to find the time it takes for the slower stone to return to the ground.

Let's assume that the initial speed of the slower stone is 'v' m/s. Therefore, the initial speed of the faster stone is 3v m/s.

We know that the time it takes for an object to reach its maximum height and return back to the ground is twice the time it takes to reach its maximum height. So, the time taken by the slower stone to return to the ground is 2 times the time taken to reach its maximum height.

Therefore, the time taken by the slower stone to return to the ground is 2(12.0) = 24.0 seconds.