Final answer:
The electric current through the 75W bulb connected to a 110V source is approximately 0.682 A, and the resistance of the bulb is roughly 161.29Ω.
Step-by-step explanation:
To determine the electric current through the bulb, we use the power equation, which states that electric power (P) is the product of voltage (V) and current (I). This can be represented as P = VI. Since we know the power (P = 75W) and the voltage (V = 110V), we can solve for the current (I). By rearranging the equation, we get I = P / V, which yields I = 75W / 110V, resulting in an electric current of approximately 0.682 A.
Next, to determine the resistance of the bulb, we can use Ohm’s Law, which states that the voltage (V) across an electric device is equal to the product of the current (I) flowing through it and its resistance (R), expressed as V = IR. Rearranging for resistance, we get R = V / I. Substituting the values obtained earlier, R = 110V / 0.682 A, we get a resistance of approximately 161.29Ω.