Final answer:
To calculate the satellite's time of eclipse, the full orbital geometry and Earth's shadow information are needed, which are not provided. If orbital period is what's sought, Kepler's third law would be used given the radius of the orbit.
Step-by-step explanation:
To calculate the time of eclipse (TE) for a satellite in a 12239km circular orbit with 0° inclination, we would typically use the geometry of the Earth-satellite-Sun system and the satellite's orbital dynamics. However, the question doesn't provide all the necessary data, such as the Earth's radius and orbital parameters to calculate the shadow cast by the Earth on the satellite's orbit. Nevertheless, if we assume that the question intends to find the orbital period of the satellite instead of the actual eclipse duration, we can use Kepler's third law to find it. Since the altitude given is the orbital distance from the center of the Earth, the orbital period (T) can be found using the formula: T = 2π√(r³/Γ), where Γ is the gravitational constant times the mass of the Earth and r is the orbital radius. The given altitude is the orbital radius since it's already measured from Earth's center. Since an exact numerical answer cannot be provided without the full equation and values for Γ, no further calculations can be made in this response. To obtain TE in minutes, the orbital period in seconds would be converted to minutes by dividing by 60.