Question

A coil of 50 loops is pulled in 0.02 s from between the poles of a magnet, where its area intercepts a flux of 3.1 x 10-4 wb, to a place where the intercepted flux is 0.1 x 10-4 Wb. Determine the average emf induced in the coil.

a. I V
b. 0.75 V
c. 3.5 V
d. 2V O

Answer 1

The average emf induced in the coil is -2 V.

Step-by-step explanation:

To calculate the average electromotive force (emf) induced in the coil, we can use the formula emf = Δϕ/Δt, where Δϕ is the change in magnetic flux and Δt is the change in time. Given that the initial flux is 3.1 x 10^-4 Wb and the final flux is 0.1 x 10^-4 Wb, and the time taken is 0.02 s, we can substitute these values into the formula and solve: emf = (0.1 x 10^-4 - 3.1 x 10^-4) / 0.02 = -2 V.

Therefore, the average emf induced in the coil is -2 V.