Question

Consider a heat transfer of 35 J to a gas while the gas does 10 J of work. After, the gas releases 20 J of heat while 4 J of work is done on the gas. Can the gas be in the same thermodynamic state at the beginning and end of this process?

Answer 1

The net change in internal energy of the system can be calculated by taking the sum of the heat transfer and the work done on the system, and subtracting the sum of the heat transfer and the work done by the system.

Step-by-step explanation:

The net change in internal energy of the system can be calculated by taking the sum of the heat transfer and the work done on the system, and subtracting the sum of the heat transfer and the work done by the system. In this case, the heat transfer to the system is 40 J and the work done by the system is 10 J, resulting in a positive change in internal energy. The heat transfer out of the system is 25 J and the work done on the system is 4 J, resulting in a negative change in internal energy.