Question

A person of mass M=60kglifts an object of mass m = 10kg upward

with acceleration a. If the magnitude of the normal force that the
person feels from the floor the person is standing on is FN=796N,

Answer 1

To find the magnitude of the acceleration, we can use Newton's second law of motion.

Step-by-step explanation:

The person is lifting an object with a mass of 10 kg upward with an acceleration of a. Given that the person feels a normal force of 796 N from the floor, we can use Newton's second law of motion to find the magnitude of the force exerted by the person:

F = ma + mg, where F is the force exerted by the person, m is the mass of the object, a is the acceleration, and g is the acceleration due to gravity. Plugging in the values:

F = (60 kg)(a) + (60 kg)(9.8 m/s^2) = 796 N

Simplifying the equation, we have:

60a + 588 = 796

60a = 208

a = 3.47 m/s^2

Therefore, the magnitude of the acceleration is 3.47 m/s^2.