Final answer:
To find the magnitude of the net electric field at point B, due to charges q1 and q2, we can use the principle of superposition. The net electric field at a point is the vector sum of the electric fields due to each individual charge. By plugging in the given values and performing the calculations, we can find the magnitude of the net electric field at point B due to q1 and q2.
Step-by-step explanation:
To find the magnitude of the net electric field at point B, due to charges q1 and q2, we can use the principle of superposition. The net electric field at a point is the vector sum of the electric fields due to each individual charge. The formula to calculate the electric field due to a point charge is:
E = k*(Q/r^2)
where E is the electric field, k is the Coulomb's constant (9x10^9 Nm^2/C^2), Q is the charge, and r is the distance from the charge to the point.
Given that q1 = 7.0x10^-6 C is at x1 = 8.50x10^-3 m from point B, and q2 = -7.5x10^-6 C is at x2 = 2.950x10^-2 m from point B, we can calculate the electric field due to each charge at point B:
E1 = k*(q1/(x1^2))
E2 = k*(q2/(x2^2))
Then, we can calculate the net electric field at point B by adding the two electric field vectors:
net Electric Field = E1 + E2
By plugging in the given values and performing the calculations, we can find the magnitude of the net electric field at point B due to q1 and q2.