Question

A parallel-plate capacitor has a capacitance of 25 µF. What

potential difference across the plates is required to store 7.2×
10−4 C on this capacitor?

Answer 1

To find the potential difference across the plates of a parallel-plate capacitor, we can use the equation: V = Q / C. Plugging in the given values, a potential difference of 2.88 V is required to store 7.2×10^-4 C on this capacitor.

Step-by-step explanation:

To find the potential difference across the plates of a parallel-plate capacitor, we can use the equation:

V = Q / C

Where V is the potential difference, Q is the charge stored on the capacitor, and C is the capacitance.

Plugging in the given values:

V = 7.2×10-4 C / 25 µF = 2.88 V

Therefore, a potential difference of 2.88 V is required to store 7.2×10-4 C on this capacitor.