The orbital period of the object in a circular orbit at 2028 km is approximately 216 minutes.
The period, or time for one orbit, is related to the radius of the orbit by Kepler's third law, given as T = 2πr/V.
In this case, the object is in a circular orbit with a radius of 2028 km. We are given the velocity of the object in the orbit as 47 km/s (Vorbit = 47 km/s).
Substituting the values into the formula, we have T = (2π * 2028) / 47. Calculating this gives us a period of approximately 216 minutes.