Final answer:
When 15.3 moles of sodium hydroxide is used, 7.65 moles of sodium sulfate will be produced.
Step-by-step explanation:
The balanced equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H₂SO4) is 2NaOH + H₂SO4 → 2H₂O + Na₂SO4. From the equation, you can see that for every 2 moles of NaOH, 1 mole of Na₂SO4 is produced. Therefore, if you have 15.3 moles of NaOH, you will produce half as many moles of Na₂SO4, which is 7.65 moles.