Question

Let's change the given values to: R1 = 38.6

ohms, R2 = 30.0 ohms, R3 = 33.5 ohms, and
I1 = 0.6 A. What is the potential drop across
R3?

Answer 1

Using Ohm's law, the potential drop across R3 when R3 = 33.5 ohms and I1 = 0.6 A is calculated to be 20.1 volts.

Step-by-step explanation:

The student has asked for the potential drop across resistor R3 when the given values are R1 = 38.6 ohms, R2 = 30.0 ohms, R3 = 33.5 ohms, and I1 = 0.6 A. To calculate the potential drop across R3, we use Ohm's law, which states that the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R). Therefore, the potential drop across R3 is V3 = I1 * R3.

Substituting the given values, we get:
V3 = 0.6 A * 33.5 Ω = 20.1 V

The potential drop across R3 is thus 20.1 volts.