Final answer:
For a perfectly elastic collision with ball A of mass m1 moving at velocity viA and ball B of mass m2 stationary, the final velocities are calculated using conservation of both momentum and kinetic energy, resulting in vfA = viA * (m1 - m2) / (m1 + m2) for ball A and vfB = 2 * m1 * viA / (m1 + m2) for ball B.
Step-by-step explanation:
When two balls of mass m1 and m2 engage in a perfectly elastic collision, where ball A is moving with velocity viA and ball B is initially stationary, the final velocities of the balls can be determined using the conservation of momentum and conservation of kinetic energy. The relevant formulas are:
For ball A (m1):
- vfA = viA * (m1 - m2) / (m1 + m2)
For ball B (m2):
- vfB = 2 * m1 * viA / (m1 + m2)
These formulas assume a one-dimensional collision with no external forces acting on the system of two balls. Remember, the final velocities are dependent on both masses and the initial velocity of the moving ball.