Question

A proton accelerates from rest in a uniform electric field of

672 N/C. At some later time, its speed is 1.16 106 m/s. (a) Find
the magnitude of the acceleration of the proton. ____ m/s2

Answer 1

The magnitude of the proton's acceleration in the given electric field is approximately 4.01 x 10²⁶ m/s².

Step-by-step explanation:

To find the magnitude of the acceleration of the proton, you can use the equation:

acceleration = electric field / mass

Given that the electric field is 672 N/C and the mass of a proton is approximately 1.67 x 10⁻²⁷ kg, you can substitute these values into the equation:

acceleration = 672 N/C / (1.67 x 10⁻²⁷ kg)

Solving for acceleration gives you a value of approximately 4.01 x 10²⁶ m/s².